**Buzz Number: It is a number that is divisible by 7 or it’s last digit is 7.****(For example 49 is divisible by 7 so it is a buzz number, 27 has 7 as it’s last digit so it is also a buzz number)**

import java. io.*;

class buzz_num

{

public static void main()throws IOException

{

BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

System.out.println(“Give a number”);

int num=Integer.parseInt(br.readLine());

int rem;

rem=num%10;

{

if(rem==7 || num%7==0)

System.out.println(“This is a buzz number”);

else

System.out.println(“This is not a buzz number”);

}

}

}

I/p:- 47

O/p:-This is a buzz number.

I/p:- 22

O/p:- This is not a buzz number.

**2. Armstrong number:-It is a number whose digits cubes sum is equal to the number(for example 153–> (1)3+(5)3+(3)3=1+125+27=153, so it is an Armstrong number)**

import java.io.*;

class armstrong

{

public static void main()throws IOException

{

BufferedReader br=new BufferedReader (new InputStreamReader(System.in));

System.out.println(“Give a number”);

int num=Integer.parseInt(br.readLine());

double rem;

int n=num;

int sum=0;

do

{

rem=num%10;

rem=(Math.pow(rem,3));

sum+=rem;

num=num/10;

}while(num!=0);

if(sum==n)

System.out.println(“This is an Armstrong number”);

else

System.out.println(“This is not an Armstrong number”);

}

}

I/p:- 135

O/p:-This is an Armstrong number.

I/p:- 123

O/p:- This is not an Armstrong number.

Hello.This post was really motivating, particularly because I was searching for thoughts on this issue last Monday.